document.write( "Question 1067237: Not sure if this is the right section or not.
\n" ); document.write( "Anyway, I'm struggling with Piecewise-defined functions. My question is about finding all the values of b that make the function continuous everywhere. \r
\n" ); document.write( "\n" ); document.write( "f(x)= (x^2-4)/x-2 x < 2,
\n" ); document.write( " [b-cos(pix/2)]^2. x >= 2 \r
\n" ); document.write( "\n" ); document.write( "Not sure how to solve it help would be great. I think I'm supposed to evaluate each at the limit as x approaches 2 but am not sure.
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Algebra.Com's Answer #683985 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The only point you're concerned with is \"x=2\" because the limit from the left must equal the limit from the right.
\n" ); document.write( "So set the two functions equal to each other when \"x=2\" and solve for \"b\" to make it so.
\n" ); document.write( "So,
\n" ); document.write( "\"%28x%5E2-4%29%2F%28x-2%29=x%2B2\" except when \"x=2\"
\n" ); document.write( "So then,
\n" ); document.write( "\"x%2B2=b-cos%28%28pi%2F2%29x%29%29\"
\n" ); document.write( "So now take the limit as x approaches 2,
\n" ); document.write( "\"2%2B2=b-cos%28%28pi%2F2%292%29\"
\n" ); document.write( "\"4=b-cos%28pi%29\"
\n" ); document.write( "\"4=b-%28-1%29\"
\n" ); document.write( "\"4=b%2B1\"
\n" ); document.write( "\"b=3\"
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