document.write( "Question 1068707: a man wants to finish a work in 150days. he employs 200 workers. He discoveres that only a quarter of the work is done in 50days. in order to complete the work on schedule, how many workers must he employ additionally? How can solve this equation? Explain ?
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Algebra.Com's Answer #683979 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Work rates, r is for rate of ONE worker. If n workers together, then rate is \"n%2Ar\". If time is t and amount of work is w, then \"nr%2At=w\". The unit for rate is \"PIECEOFWORK%2FTIME\".\r
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\n" ); document.write( "\n" ); document.write( "Two hundred workers each at rate r worked for 50 days and completed one quarter of the whole piece of work:
\n" ); document.write( "\"200r%2A50=1%2F4\".
\n" ); document.write( "Solve this for r.\r
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\n" ); document.write( "\n" ); document.write( "Next, the \"man\" still wants to complete the remaining \"3%2F4\" of the work in 100 days. How many workers needed, n, for this? Note, he already has 200 workers. Let N be how many of the added workers.\r
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\n" ); document.write( "\n" ); document.write( "\"%28N%2B200%29%2Ar%2A100=%283%2F4%29\"
\n" ); document.write( "You should now already have the value of r.
\n" ); document.write( "Solve for N.\r
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\n" ); document.write( "\"200r%2A50=1%2F4\"
\n" ); document.write( "\"r=1%2F%28200%2A50%2A4%29\"
\n" ); document.write( "\"r=1%2F40000\"
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\n" ); document.write( "\"N%2B200=%283%2F4%29%281%2F%28100r%29%29\"
\n" ); document.write( "\"N=%283%2F4%29%281%2F%28100r%29%29-200\"\r
\n" ); document.write( "\n" ); document.write( "\"N=%283%2F%28400r%29%29-200\"\r
\n" ); document.write( "\n" ); document.write( "\"N=3%2F%28400%281%2F40000%29%29-200\"\r
\n" ); document.write( "\n" ); document.write( "\"N=3%2F%281%2F100%29-200\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28N=100%29\"
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