document.write( "Question 1068633: Passenger comfort is influenced by the amount of pressurization in an airline cabin. Higher pressurization allows a closer-to-normal environment and a more relaxed flight. A study by an airline user group recorded the corresponding air pressure on 30 randomly chosen flights. The study revealed a mean equivalent pressure of 8000 feet with a standard deviation of 300 feet.\r
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document.write( " Develop a 99% confidence interval for the population mean equivalent pressure.\r
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document.write( " How large a sample is needed to find the population mean within 25 feet at 95% confidence?
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Algebra.Com's Answer #683956 by Boreal(15235) You can put this solution on YOUR website! CI is 8000+/-t df=29,0.995 *300/sqrt(30); t value is 2.756 \n" ); document.write( "interval width is 2.756*300/sqrt(30)=150.95 \n" ); document.write( "(7849,8151) \n" ); document.write( "---------------- \n" ); document.write( "interval is 25=z*300/sqrt(n) \n" ); document.write( "I use z, because the sample size is large, and I can always then use t for that df and see if it changes the result. \n" ); document.write( "25=1.96*300/sqrt(n) \n" ); document.write( "25 sqrt(n)=1.96*300=588 \n" ); document.write( "sqrt(n)=588/25=23.52 \n" ); document.write( "square both sides \n" ); document.write( "n=553.19 round to 554. With this size sample, t=z. \n" ); document.write( "When I use this in the calculator for a t-test, I get an interval of +/-25. \n" ); document.write( " |