document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068698>Question 1068698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rationalize the denominator and simplify 5 divided by 4-&#8730;3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683953 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply top and bottom by the conjugate of the denominator<BR>\n" );
document.write( "that would be 4 + sqrt(3)<BR>\n" );
document.write( "the numerator becomes 5(4+ sqrt(3))=20+5 sqrt(3) <BR>\n" );
document.write( "the denominator becomes (4- sqrt(3))(4+ sqrt(3))=16-3=13, because the internal products 4 sqrt(3) and -4 sqrt (3) cancel each other.<BR>\n" );
document.write( "The top can be left as [5(4+sqrt (3)]/13<BR>\n" );
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