document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068684>Question 1068684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that is perpendicular to the line 2x+3y=-17 and which passes through point (2,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683950 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+3y=-17<BR>\n" );
document.write( "3y=-2x-17<BR>\n" );
document.write( "y=(-2/3)x-17/3.  That slope is -2/3<BR>\n" );
document.write( "The line perpendicular to that has a slope that is the negative reciprocal, or 3/2<BR>\n" );
document.write( "point-slope y-y1=m(x-x1) m is slope and (x1,y1) is point.<BR>\n" );
document.write( "y-5=(3/2)(x-2)<BR>\n" );
document.write( "y-5=(3/2)x-3<BR>\n" );
document.write( "y=(3/2)x+2<BR>\n" );
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