document.write( "Question 1068696: A company that has a large number of supermarket grocery stores claims that customers who pay by personal checks spend an average of $87 on groceries at these stores with a standard deviation of $22. Assume that the expenses incurred on groceries by all such customers at these stores are normally distributed. What percentage of customers paying by check spend between $59.94
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document.write( "and $68.96 on groceries?
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Algebra.Com's Answer #683945 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "=(87-59.94)/22=27.06/22=1.23 \n" ); document.write( "=(87-68.96)/22=18.04/22=0.82 \n" ); document.write( "Want the probability z is between those two values \n" ); document.write( "p=0.0968 or 9.68% \n" ); document.write( " |