document.write( "Question 1068645: solve the equation:
\n" ); document.write( "logx(x+2)+logx(x+3)=2
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Algebra.Com's Answer #683908 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
logx(x+2)+logx(x+3)=2
\n" ); document.write( "If x is the base:
\n" ); document.write( "\"log%28x%2C%28x%2B2%29%2A%28x%2B3%29%29+=+log%28x%2Cx%5E2%29\"
\n" ); document.write( "\"%28x%2B2%29%2A%28x%2B3%29+=+x%5E2\"
\n" ); document.write( "\"x%5E2+%2B+5x+%2B+6+=+x%5E2\"
\n" ); document.write( "5x = -6
\n" ); document.write( "x = -6/5
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\n" ); document.write( "A negative base won't work.
\n" ); document.write( "No solution.\r
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