document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068538>Question 1068538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a bit of an issue solving sqrt(3x+1)-sqrt(x-1)=2 or &#8730;3x+1-&#8730;x-1 = 2\r<BR>\n" );
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document.write( "This is what I have done so far:\r<BR>\n" );
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document.write( "   &#8730;3x+1 = &#8730;x-1+2  \r<BR>\n" );
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document.write( "=> (&#8730;3x+1)2 = (&#8730;x-1+2)2\r<BR>\n" );
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document.write( "=> 3x+1 = x-1+4+4&#8730;x-1\r<BR>\n" );
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document.write( "=> -4&#8730;x-1 = -3x-1+x-1+4  or is it 4 &#8730;x+1 = -3x-1+x-1+4?\r<BR>\n" );
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document.write( "=>  4&#8730;x-1 = 2x-2  *This is where I get lost.  I have seen this as -2x+2 as well.  I am really confused at this point and need to get to the next steps.\r<BR>\n" );
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document.write( "Thank you for your help in advance.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683762 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> &#8730;3x+1 = &#8730;x-1+2 <BR>\n" );
document.write( "=> (&#8730;3x+1)^2 = 2+ sqrt (x-1)<BR>\n" );
document.write( "=> 3x+1 = 4 +4 sqrt(x-1)+x-1.  I like to bring the smaller x to the side with the larger and keep it positive but one doesn't have to do that.<BR>\n" );
document.write( "=2x-2=4 sqrt(x-1).  <BR>\n" );
document.write( "***square both sides***remember to square the 4, too.<BR>\n" );
document.write( "4x^2-8x+4=16(x-1)=16x-16<BR>\n" );
document.write( "4x^2-24x+20=0<BR>\n" );
document.write( "x^2-6x+5=0<BR>\n" );
document.write( "(x-5)(x-1)=0<BR>\n" );
document.write( "x=5 and 1<BR>\n" );
document.write( "sqrt(16)-sqrt(4)=4-2=2 checks<BR>\n" );
document.write( "sart(4)-sqrt(0)=2 also checks. </SPAN>\n" );
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