document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068538>Question 1068538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a bit of an issue solving sqrt(3x+1)-sqrt(x-1)=2 or &#8730;3x+1-&#8730;x-1 = 2\r<BR>\n" );
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document.write( "This is what I have done so far:\r<BR>\n" );
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document.write( "   &#8730;3x+1 = &#8730;x-1+2  \r<BR>\n" );
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document.write( "=> (&#8730;3x+1)2 = (&#8730;x-1+2)2\r<BR>\n" );
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document.write( "=> 3x+1 = x-1+4+4&#8730;x-1\r<BR>\n" );
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document.write( "=> -4&#8730;x-1 = -3x-1+x-1+4  or is it 4 &#8730;x+1 = -3x-1+x-1+4?\r<BR>\n" );
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document.write( "=>  4&#8730;x-1 = 2x-2  *This is where I get lost.  I have seen this as -2x+2 as well.  I am really confused at this point and need to get to the next steps.\r<BR>\n" );
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document.write( "Thank you for your help in advance.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683760 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4sqrt%28x-1%29=2x-2 ALIGN=MIDDLE  ALT=\"4sqrt%28x-1%29=2x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > is correct.<BR>\n" );
document.write( "Keep going.<BR>\n" );
document.write( "Now square both sides again.<BR>\n" );
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