document.write( "Question 93858: write in standard form. state wheather the graph is a parabola, circle,ellipse, or hyperbola. and graph the equation...?\r
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document.write( "6x^2+ 6y^2=162 \n" );
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Algebra.Com's Answer #68374 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 6x^2+6y^2=162 reducing this equation by diviving all terms by 6 we get \n" ); document.write( "x^2+y^2=27 now settong x=0 & solve for y we get \n" ); document.write( "0^2+y^2=27 \n" ); document.write( "y^2=27 \n" ); document.write( "y=sqrt27 \n" ); document.write( "y=+/-5.196 answer for the y intercepts of(0,5.196)(0,-5.196) \n" ); document.write( "Now set y=0 & solve for x we get \n" ); document.write( "x^2+0^2=27 \n" ); document.write( "x^2=27 \n" ); document.write( "x=sqrt27 \n" ); document.write( "x=+/-5.196 answer for the x intercepts of (5.196,0)(-5.196,0) \n" ); document.write( "Thus one could conclude that this is a circle with an origin of (0,0) & a radius of 5.196 units. \n" ); document.write( " |