document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93853>Question 93853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 50 m.  the width of a triangle is 5 m less the the length. Find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68371 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2(L-5)=50<BR>\n" );
document.write( "2L+2L-10=50<BR>\n" );
document.write( "4L=50+10<BR>\n" );
document.write( "4L=60<BR>\n" );
document.write( "L-60/4<BR>\n" );
document.write( "L=15 FOR THE LENGTH.<BR>\n" );
document.write( "L-5=10 FOR THE WIDTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*15=2*10=50<BR>\n" );
document.write( "30+20=50<BR>\n" );
document.write( "50=50 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );