document.write( "Question 1068448: An alloy contains 80% bronze and 20% tin. An other alloy contains 85% bronze and 12% tin.find the ratio of mixing both alloys such that 15% tin should be in mixture.also find % of bronze . \n" ); document.write( "
Algebra.Com's Answer #683672 by ankor@dixie-net.com(22740)\"\" \"About 
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An alloy contains 80% bronze and 20% tin.
\n" ); document.write( " An other alloy contains 85% bronze and 12% tin.
\n" ); document.write( "find the ratio of mixing both alloys such that 15% tin should be in mixture.
\n" ); document.write( "also find % of bronze .
\n" ); document.write( ":
\n" ); document.write( "Assume an amt of 120 units in the original mixture,
\n" ); document.write( "let x = the amt of the 2nd mixture required to obtain 15% tin
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\n" ); document.write( "Write a mixture equation based on the amt of tin
\n" ); document.write( ".20(120) + .12x = .15(x+120)
\n" ); document.write( "24 + .12x = .15x + 18
\n" ); document.write( "24 - 18 = .15x - .12x
\n" ); document.write( "6 = .03x
\n" ); document.write( "x = 6/.03
\n" ); document.write( "x = 200 units of the 2nd mixture to be added to the 120 units of the original
\n" ); document.write( "Find the ratio of these two
\n" ); document.write( "\"120%2F200\" = 3:5
\n" ); document.write( ":
\n" ); document.write( "The % bronze of the 2nd mixture is given as 85% and 12% tin. These do not add up to 100%, so something is wrong here
\n" ); document.write( ":
\n" ); document.write( "Anyway, if you have 15% tin you have 85% bronze
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