document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068438>Question 1068438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A takes one hour to run a certain distance. B takes 40 minutes to run the same distance.One day A started his running at 4 p.m and B started his running 10 minutes later. What is the time when B passes A? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683649 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distance in each of the described rates is its own distance unit.\r<BR>\n" );
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document.write( "Using all time quantities in MINUTES and using the catching-up distance as d:<BR>\n" );
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document.write( "A         1/60        t+10          d\r\n" );
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document.write( "B         1/40         t            d\r\n" );
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document.write( "Solve for the amount of time in minutes that both A and B ran.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F60%29%28t%2B10%29=%281%2F40%29t ALIGN=MIDDLE  ALT=\"%281%2F60%29%28t%2B10%29=%281%2F40%29t\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t=20%2Aminutes ALIGN=MIDDLE  ALT=\"t=20%2Aminutes\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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