document.write( "Question 1068367: Tyler has two saving accounts. One of the accounts pays 7% annual interest,the other account pays 9% annual interest. If you have $400.00 more invested at 9% than you invested at 7%,how much do you have invested in each account if the total amount of interest you earn in a year is $68.00 \n" ); document.write( "
Algebra.Com's Answer #683583 by addingup(3677)\"\" \"About 
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0.07x+0.09(x+400) = 68
\n" ); document.write( "0.07x+0.09x+36 = 68
\n" ); document.write( "0.16x = 32
\n" ); document.write( "x = 200
\n" ); document.write( "Tyler has 200 invested at 7% and 200+400= 600 invested at 9%
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\n" ); document.write( "Check:
\n" ); document.write( "0.07 * 200 = 14
\n" ); document.write( "0.09 * 600 = 54
\n" ); document.write( "Total . . . 68 Correct
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