document.write( "Question 93837: If a and b are not equal, but ax=bx is a true statement, then find the numerical value of 2x (a+b). \r
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Algebra.Com's Answer #68353 by jim_thompson5910(35256)\"\" \"About 
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\"ax=bx\"\r
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\n" ); document.write( "\n" ); document.write( "\"ax-bx=0\" Subtract \"bx\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%28a-b%29=0\" Factor out x\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2F%28a-b%29\" Divide both sides by \"a-b\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" Divide both sides by \"a-b\"\r
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\n" ); document.write( "\n" ); document.write( "Note: If we let x=0, we get \"a%280%29=b%280%29\" which becomes \"0=0\" and it will be true for any value of a and b\r
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\n" ); document.write( "\n" ); document.write( "So that means if we evaluate \"2x%28a%2Bb%29\" with x=0, we get\r
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\n" ); document.write( "\n" ); document.write( "\"2%280%29%28a%2Bb%29\" Plug in x=0\r
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\n" ); document.write( "\n" ); document.write( "\"0%28a%2Bb%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"a%280%29%2Bb%280%29\"Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"0%2B0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"0\" Add\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%28a%2Bb%29=0\"
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