document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068296>Question 1068296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In triangle abc ,angle a=x+20,angle b=2x-20,angle c=3/2x.show that the triangle is equilateral </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683516 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angles a + b + c = 180 degrees (sum of the angles of any triangle)<BR>\n" );
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document.write( "x+20 + 2x-20 + 3x/2 = 180<BR>\n" );
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document.write( "3x + 3x/2 = 180<BR>\n" );
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document.write( "6x/2 + 3x/2 = 180<BR>\n" );
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document.write( "9x/2 = 180<BR>\n" );
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document.write( "9x = 360<BR>\n" );
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document.write( "x = 40<BR>\n" );
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document.write( "a = 40+20 = 60<BR>\n" );
document.write( "b = 2 * 40 - 20 = 60<BR>\n" );
document.write( "c = 3 * 40 / 2 = 60<BR>\n" );
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document.write( "a = b = c = 60<BR>\n" );
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document.write( "triangle abc is equalateral since all three angles are equal<BR>\n" );
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