document.write( "Question 1068252: what is the answer of if a cubicaltank has 6m long 3m height and
\n" ); document.write( "105 volume What is the width? with solution
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Algebra.Com's Answer #683421 by Lightning_Fast(78)\"\" \"About 
You can put this solution on YOUR website!
Well we know that volume is equal to length time width times height.\r
\n" ); document.write( "\n" ); document.write( "We can translate this to algebraic form as: \"V=L%2AW%2AH\"\r
\n" ); document.write( "\n" ); document.write( "From your problem, we are given the following:
\n" ); document.write( "Cubical tank is:
\n" ); document.write( "- 6m long (length)
\n" ); document.write( "- 3m height (height)
\n" ); document.write( "- 105m volume (volume)\r
\n" ); document.write( "\n" ); document.write( "Let's plug in what we know:
\n" ); document.write( "\"105=6%2AW%2A3\"\r
\n" ); document.write( "\n" ); document.write( "We were not given the width, so let's solve for it!\r
\n" ); document.write( "\n" ); document.write( "\"105=6%2AW%2A3\"
\n" ); document.write( "Divide both sides by 18 to get:
\n" ); document.write( "\"105%2F18=W+\"\r
\n" ); document.write( "\n" ); document.write( "This simplifies to\"15.833333333...=W+\" on a calculator\r
\n" ); document.write( "\n" ); document.write( "Your final answer would be:
\n" ); document.write( "The width of the cubical tank is about 15.83 meters wide.\r
\n" ); document.write( "\n" ); document.write( "By the way, the tank would not be a cubical since all four sides would have to be the same (which they are not). In other words, 105 is not a perfect cube.\r
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