document.write( "Question 1068200: Trajectory of a Projectile the height in meters of a ball released from a ramp is given by the function h(t) = -4.9t^2+29.4t+34.3, where (t) represents the end of the ramp.
\n" ); document.write( " Determine the time interval that the ball is above 50 m.
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Algebra.Com's Answer #683403 by ankor@dixie-net.com(22740)\"\" \"About 
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Trajectory of a Projectile the height in meters of a ball released from a ramp is given by the function h(t) = -4.9t^2+29.4t+34.3, where (t) represents the end of the ramp.
\n" ); document.write( " Determine the time interval that the ball is above 50 m.
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\n" ); document.write( "h(t) = 50 meters
\n" ); document.write( "-4.9t^2 + 29.4t + 34.3 = 50
\n" ); document.write( "-4.9t^2 + 29.4t + 34.3 - 50 = 0
\n" ); document.write( "-4.9t^2 + 29.4t - 15.7 = 0
\n" ); document.write( "Use the quadratic formula to find t, I got
\n" ); document.write( "t = .59 seconds, 50 ft on the way up
\n" ); document.write( "and
\n" ); document.write( "t = 5.41 seconds, 50 ft on the way down
\n" ); document.write( "therefore
\n" ); document.write( "5.41 - .59 = 4.82 seconds it was at or above 50 ft
\n" ); document.write( ":
\n" ); document.write( "Graphically,the green line is 50 ft
\n" ); document.write( " \"+graph%28+300%2C+200%2C+-4%2C+8%2C+-10%2C+100%2C+-4.9x%5E2%2B29.4x%2B34.3%2C+50%29+\"
\n" ); document.write( "You can see the time interval above 50 m is almost 5 seconds
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