document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068232>Question 1068232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many grams of pure acid must be added to 40 grams of a 20% acid solution to make a solution that is 36% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683398 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=grams of pure acid.<BR>\n" );
document.write( "pure acid formula .20(40)+1.00(x)=.36(40+x)<BR>\n" );
document.write( "8+x=14.4+.36x<BR>\n" );
document.write( "0.64x=6.4<BR>\n" );
document.write( "x=10 gms.<BR>\n" );
document.write( "10 is 1/5 of the final amount<BR>\n" );
document.write( "36% is 1/5 of the way between 20% and 100% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );