document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066568>Question 1066568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A goat is tethered to a corner of a regular hexagonal house which is in the middle of a grassy plain. The hexagon measure ten feet on a side. The rope stretches half way around the hexagon. Find the area of grass that the goat can reach. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683359 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A goat is tethered to a corner of a regular hexagonal house which is in the middle of a grassy plain. The hexagon measure ten feet on a side. The rope stretches half way around the hexagon. Find the area of grass that the goat can reach.<BR>\n" );
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document.write( "The 1st sector is radius 10 and a central angle of pi/3 --> area of 10pi/3<BR>\n" );
document.write( "The 2nd sector is radius 20 and a central angle of pi/3 --> area of 20pi/3<BR>\n" );
document.write( "The 3rd sector is radius 30 and a central angle of 2pi/3 --> area of 20pi<BR>\n" );
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document.write( "That's 1/2 the area, = 30pi sq ft, it's symmetrical.<BR>\n" );
document.write( "Total area = 60pi sq feet<BR>\n" );
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