document.write( "Question 1068163:  A jet plane traveling at
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document.write( "500 mph overtakes a propeller plane traveling at
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document.write( "150 mph that had a 
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document.write( "3-hour head start. How far from the starting point are the planes \n" );
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| Algebra.Com's Answer #683324 by Boreal(15235)     You can put this solution on YOUR website! propeller plane leaves at t=0 \n" ); document.write( "jet plane leaves 3 hours later \n" ); document.write( "time both have traveled is 3+t hours for propeller and t hours for jet \n" ); document.write( "Distance is rate*time, and both distances are equal. \n" ); document.write( "150(3+t)=500t \n" ); document.write( "450+150t=500t \n" ); document.write( "450=350t \n" ); document.write( "t=450/350=9/7 hours \n" ); document.write( "In that time, the jet has traveled 500*(9/7)=642.86 miles \n" ); document.write( "the propeller plane traveled 150(30/7)=4500/7, same as above. \n" ); document.write( " |