document.write( "Question 93817This question is from textbook algebra and trigonometry
\n" ); document.write( ": someone show me how to solve this?? If an observer is 200ft from a building and the angle of elevation to the top of a building is 60 degrees, what is the height of the building?can \n" ); document.write( "
Algebra.Com's Answer #68332 by stanbon(75887)\"\" \"About 
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If an observer is 200ft from a building and the angle of elevation to the top of a building is 60 degrees, what is the height of the building?
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\n" ); document.write( "Draw the picture.
\n" ); document.write( "If the angle of inclination is 60 degrees and the building forms a right
\n" ); document.write( "triangle with the ground, the 3rd angle of the triangle formed is 30 degrees.
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\n" ); document.write( "The side opposite the 30 degree angle is (1/2) the hypotenuse.
\n" ); document.write( "That side opposite is 200 ft so the hypotenuse is 400 ft.
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\n" ); document.write( "Use Pythagoras to find the 3rd side of the right triangle which is the building.
\n" ); document.write( "400^2 = 200^2 + x^2
\n" ); document.write( "x^2 = 160000 - 40000 = 120000
\n" ); document.write( "x = 346.41 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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