document.write( "Question 1068136: A boat can go 20 miles against a current in the same time that it can go 60 miles with the current. The current is 4 mph. Find the rate of the boat in still water. \n" ); document.write( "

Algebra.Com's Answer #683306 by stanbon(75887) $\"\"$ $\"About$

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A boat can go 20 miles against a current in the same time that it can go 60 miles with the current. The current is 4 mph. Find the rate of the boat in still water.
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\n" ); document.write( "With Current DATA:
\n" ); document.write( "rate = b+4 mph ; time = t hrs ; distance 60 miles
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\n" ); document.write( "Against Current DATA:
\n" ); document.write( "rate = b-4 mph ; time = t hrs ; distance = 20 miles
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\n" ); document.write( "Equations:
\n" ); document.write( "bt + 4t = 60
\n" ); document.write( "bt - 4t = 20
\n" ); document.write( "-------------------
\n" ); document.write( "8t = 40
\n" ); document.write( "time = 5 hrs
\n" ); document.write( "------
\n" ); document.write( "rate in still water ::
\n" ); document.write( "(b+4)5 = 60
\n" ); document.write( "b+4 = 12
\n" ); document.write( "Ans: boat = 8 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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