document.write( "Question 1068027: The hypotenuse of a right triangle is four times its base. If B is the base of the triangle, express the area of the triangle A as a function of B. \r
\n" ); document.write( "\n" ); document.write( "(A) A= 2b^2
\n" ); document.write( "(B) A= (sqrt(3) b^2) /2
\n" ); document.write( "(C) A= sqrt(3) b^2
\n" ); document.write( "(D) A= 2 sqrt(15) b^2
\n" ); document.write( "(E) A = (sqrt(15)b^2)/2
\n" ); document.write( "

Algebra.Com's Answer #683266 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
h-hypotenuse
\n" ); document.write( "b-base
\n" ); document.write( "a-height
\n" ); document.write( "A-area
\n" ); document.write( ".
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\n" ); document.write( "\n" ); document.write( "\"h=4b\"
\n" ); document.write( "You also know,
\n" ); document.write( "\"a%5E2%2Bb%5E2=h%5E2\"
\n" ); document.write( "\"a%5E2%2Bb%5E2=%284b%29%5E2\"
\n" ); document.write( "\"a%5E2=16b%5E2-b%5E2\"
\n" ); document.write( "\"a%5E2=15b%5E2\"
\n" ); document.write( "\"a=sqrt%2815%29b\"
\n" ); document.write( "So then the area,
\n" ); document.write( "\"A=%281%2F2%29ba\"
\n" ); document.write( "\"A=%281%2F2%29b%2Asqrt%2815%29b\"
\n" ); document.write( "\"A=%28sqrt%2815%29%2F2%29b%5E2\"
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