document.write( "Question 93781: Can someone please help me out with this equation please?
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document.write( " A dr office mixed a 75% disinfectant solution with a 25% disinfectant solution. How many liters of each were used to make 20L of a 40% disinfectant solution. Thanks \n" );
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Algebra.Com's Answer #68323 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x=number of liters of 75% solution\r \n" ); document.write( "\n" ); document.write( "Then 20-x=number of liters of 25% soluton\r \n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure disinfectant in the 75% solution (0.75x) plus the amount of pure disinfectant in the 25% solution(0.25(20-x)) must equal the amount of pure disinfectant in the final mixture (0.40(20)). So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "0.75x+0.25(20-x)=0.40*20 get rid of parens\r \n" ); document.write( "\n" ); document.write( "0.75x+5-0.25x=8 subtract 5 from both sides\r \n" ); document.write( "\n" ); document.write( "0.75x+5-5-0.25x=8-5 collect like terms\r \n" ); document.write( "\n" ); document.write( "0.50x=3 divide both sides by 0.50\r \n" ); document.write( "\n" ); document.write( "x=6 liters -------------------------amount of 75% solution needed\r \n" ); document.write( "\n" ); document.write( "20-x=20-6=14 liters---------------------amount of 25% solution needed\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "6*0.75+14*0.25=20*0.40 \n" ); document.write( "4.5+3.5=8 \n" ); document.write( "8=8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---------------------ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |