document.write( "Question 93779: After a test, a teacher worked out the average mark for her class of 10 pupils. It was 81%\r
\n" ); document.write( "\n" ); document.write( "One of the pupils scored only 27%, which was much less than any of the other marks.\r
\n" ); document.write( "\n" ); document.write( "The teacher decided to work out a new average, leaving out the lowest mark. What was the new average?
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Algebra.Com's Answer #68319 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x=sum of the scores of the remaining students \r
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\n" ); document.write( "\n" ); document.write( "First write the percentages in decimal form by dividing by 100:\r
\n" ); document.write( "\n" ); document.write( "81 percent=\"81%2F100=0.81\"\r
\n" ); document.write( "\n" ); document.write( "27 percent=\"27%2F100=0.27\"\r
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\n" ); document.write( "\n" ); document.write( "\"%280.27%2Bx%29%2F10=0.81\" Set up the equation which represents the average (note: the average can be found by adding up everyone's scores and dividing that sum by the number of students who took the test)\r
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\n" ); document.write( "\n" ); document.write( "\"0.27%2Bx=8.10\" Multiply both sides by 10\r
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\n" ); document.write( "\n" ); document.write( "\"x=7.83\" Subtract 0.27 from both sides\r
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\n" ); document.write( "\n" ); document.write( "So the sum of the scores for the remaining 9 students is 7.83. Now divide this sum by 9 to find the new average\r
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\n" ); document.write( "\n" ); document.write( "\"7.83%2F9=0.87\"\r
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\n" ); document.write( "\n" ); document.write( "Now multiply 0.87 by 100 to get a percentage\r
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\n" ); document.write( "\n" ); document.write( "\"0.87%2A100=87\"\r
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\n" ); document.write( "\n" ); document.write( "So the new average is 87%
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