document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068005>Question 1068005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when you divide Brian's farther age by 2,3,4,5 or 6 the remainder is 1. if Brian's faryher is less than 100 years how old is he </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #683166 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=683166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> least common multiple of 2, 3, 4, 5, 6 is 60, i believe.<BR>\n" );
document.write( "60/2 = 30<BR>\n" );
document.write( "60/3 = 20<BR>\n" );
document.write( "60/4 = 15<BR>\n" );
document.write( "60/5 = 12<BR>\n" );
document.write( "60/6 = 10<BR>\n" );
document.write( "add one to 60 and you should get your answer.<BR>\n" );
document.write( "61/2 = 30 with a remainder of 1.<BR>\n" );
document.write( "61/3 = 20 with a remainder of 1.<BR>\n" );
document.write( "61/4 = 15 with a remainder of 1.<BR>\n" );
document.write( "61/5 = 12 with a remainder of 1.<BR>\n" );
document.write( "61/6 = 10 with a remainder of 1.\r<BR>\n" );
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