document.write( "Question 1067953: Rap is three times as old as joseph,and Don is five more than twice as old as Joseph. If the sum of their ages is 29,then how old are they now? \n" ); document.write( "
Algebra.Com's Answer #683146 by geo_freak(10)\"\" \"About 
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Let's have Joseph's age be x. \r
\n" ); document.write( "\n" ); document.write( "We know Rap is \"three times as old as Joseph\" = 3x
\n" ); document.write( "We know Don is \"five more than twice as old as Joseph\" = 5 + 2x. \r
\n" ); document.write( "\n" ); document.write( "The sum of all of their ages (x, 3x, and 5 + 2x) is equal to 29. \r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+3x+%2B+5+%2B+2x+=+29\"
\n" ); document.write( "Solve for x. \r
\n" ); document.write( "\n" ); document.write( "\"6x+%2B+5+=+29\"
\n" ); document.write( "\"6x+=+24\"
\n" ); document.write( "\"x+=+4\"\r
\n" ); document.write( "\n" ); document.write( "Joseph's age is 4, so Rap's age is 3(4) = 12 and Don's age is 5 + 2(4) = 13.\r
\n" ); document.write( "\n" ); document.write( "Check: 4 + 12 + 13 = 29 (this works!) \r
\n" ); document.write( "\n" ); document.write( "ANSWER:
\n" ); document.write( "JOSEPH = 4 years old
\n" ); document.write( "RAP = 12 years old
\n" ); document.write( "DON = 13 years old
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