document.write( "Question 1067945: make a conjecture about the number of squares in the nth sketch:
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document.write( "pattern1: 3 squares, pattern 2: 5 squares,pattern 3:7 squares and so fourth
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document.write( "MY ANSWER? I CAN CONJECTURE THAT IF THE PATTERN CONTINUES YOU CAN ADD 2 TO THE PREVIOUS COUNTING NUMBER TO GET THE NEXT TERM. is this right? \n" );
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Algebra.Com's Answer #683135 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your conjecture is correct, but that doesn't tell you how many squares are in the nth sketch.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can make a list as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "sketch number number of squares formula\r\n" ); document.write( "\r\n" ); document.write( "1 3 2 * 1 + 1\r\n" ); document.write( "2 5 2 * 2 + 1\r\n" ); document.write( "3 7 2 * 3 + 1\r\n" ); document.write( "4 9 2 * 4 + 1\r\n" ); document.write( "5 11 2 * 5 + 1\r\n" ); document.write( "6 13 2 * 6 + 1\r\n" ); document.write( ".\r\n" ); document.write( ".\r\n" ); document.write( ".\r\n" ); document.write( "n 2 * n + 1\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your next number of squares will always be 1 more than 2 times the sketch number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |