document.write( "Question 1067947: (x/2 - 3) / 4+x this whole is > 1 \n" ); document.write( "
Algebra.Com's Answer #683129 by rothauserc(4718) You can put this solution on YOUR website! (x/2 - 3) / 4+x > 1 \n" ); document.write( ": \n" ); document.write( "multiply both sides of > by (4+x) \n" ); document.write( ": \n" ); document.write( "x/2 - 3 > 4 + x \n" ); document.write( ": \n" ); document.write( "subtract x from both sides of > \n" ); document.write( ": \n" ); document.write( "-x/2 - 3 > 4 \n" ); document.write( ": \n" ); document.write( "add 3 to both sides of > \n" ); document.write( ": \n" ); document.write( "-x/2 > 7 \n" ); document.write( ": \n" ); document.write( "multiply both sides of > by 2 \n" ); document.write( ": \n" ); document.write( "-x > 14 \n" ); document.write( ": \n" ); document.write( "x < -14 \n" ); document.write( ": \n" ); document.write( "Note reverse the > sign when multiplying by a negative value \n" ); document.write( ": \n" ); document.write( " |