document.write( "Question 1067947: (x/2 - 3) / 4+x this whole is > 1 \n" ); document.write( "
Algebra.Com's Answer #683129 by rothauserc(4718)\"\" \"About 
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(x/2 - 3) / 4+x > 1
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\n" ); document.write( "multiply both sides of > by (4+x)
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\n" ); document.write( "x/2 - 3 > 4 + x
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\n" ); document.write( "subtract x from both sides of >
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\n" ); document.write( "-x/2 - 3 > 4
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\n" ); document.write( "add 3 to both sides of >
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\n" ); document.write( "-x/2 > 7
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\n" ); document.write( "multiply both sides of > by 2
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\n" ); document.write( "-x > 14
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\n" ); document.write( "x < -14
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\n" ); document.write( "Note reverse the > sign when multiplying by a negative value
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