document.write( "Question 93773: will you please explain to me how to do this using an equation. i am so lost.
\n" ); document.write( " It says, find the equation of the line that is perpendicular to -2x+7y=13 and passes through the point (6,0)
\n" ); document.write( "If you could help me, that would be wonderful. thank you and God bless.
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Algebra.Com's Answer #68310 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First convert -2x+7y=13 into slope intercept form\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"-2x%2B7y=13\" Start with the given equation


\"-2x%2B7y%2B2x=13%2B2x\" Add 2x to both sides


\"7y=2x%2B13\" Simplify


\"%287y%29%2F%287%29=%282x%2B13%29%2F%287%29\" Divide both sides by 7 to isolate y


\"y+=+%282x%29%2F%287%29%2B%2813%29%2F%287%29\" Break up the fraction on the right hand side


\"y+=+%282%2F7%29x%2B13%2F7\" Reduce and simplify


The original equation \"-2x%2B7y=13\" (standard form) is equivalent to \"y+=+%282%2F7%29x%2B13%2F7\" (slope-intercept form)


The equation \"y+=+%282%2F7%29x%2B13%2F7\" is in the form \"y=mx%2Bb\" where \"m=2%2F7\" is the slope and \"b=13%2F7\" is the y intercept.



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\n" ); document.write( "\n" ); document.write( "Now lets find the equation of the perpendicular line\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"2%2F7\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%282%2F7%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%287%2F2%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=-7%2F2\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"-7%2F2\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"-7%2F2\" (its the negative reciprocal of \"2%2F7\" from the line \"y=%282%2F7%29%2Ax%2B13%2F7\").\n" ); document.write( "Also since the unknown line goes through (6,0), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-0=%28-7%2F2%29%2A%28x-6%29\" Plug in \"m=-7%2F2\", \"x%5B1%5D=6\", and \"y%5B1%5D=0\"
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\n" ); document.write( " \"y-0=%28-7%2F2%29%2Ax%2B%287%2F2%29%286%29\" Distribute \"-7%2F2\"
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\n" ); document.write( " \"y-0=%28-7%2F2%29%2Ax%2B42%2F2\" Multiply
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\n" ); document.write( " \"y=%28-7%2F2%29%2Ax%2B42%2F2%2B0\"Add \"0\" to both sides to isolate y
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\n" ); document.write( " \"y=%28-7%2F2%29%2Ax%2B42%2F2%2B0%2F2\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%28-7%2F2%29%2Ax%2B42%2F2\" Combine the fractions
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\n" ); document.write( " \"y=%28-7%2F2%29%2Ax%2B21\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%282%2F7%29%2Ax%2B13%2F7\" and goes through (\"6\",\"0\") is \"y=%28-7%2F2%29%2Ax%2B21\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%282%2F7%29%2Ax%2B13%2F7\" and \"y=%28-7%2F2%29%2Ax%2B21\"
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\n" ); document.write( " graph of the given equation \"y=%282%2F7%29%2Ax%2B13%2F7\" (red) and graph of the line \"y=%28-7%2F2%29%2Ax%2B21\"(green) that is perpendicular to the given graph and goes through (\"6\",\"0\")
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