document.write( "Question 93772: will you please explain to me how to do this using an equation. i am so lost.
\n" ); document.write( " It says, find the slope and equation of the line through the points (-2,5) and (3,-1)
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Algebra.Com's Answer #68308 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First lets find the slope through the points (\"-2\",\"5\") and (\"3\",\"-1\")\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-1-5%29%2F%283--2%29\" Plug in \"y%5B2%5D=-1\",\"y%5B1%5D=5\",\"x%5B2%5D=3\",\"x%5B1%5D=-2\" (these are the coordinates of given points)\r
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\n" ); document.write( "\n" ); document.write( "\"m=+-6%2F5\" Subtract the terms in the numerator \"-1-5\" to get \"-6\". Subtract the terms in the denominator \"3--2\" to get \"5\"\r
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\n" ); document.write( "\n" ); document.write( "So the slope is\r
\n" ); document.write( "\n" ); document.write( "\"m=-6%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point-slope formula to find the equation of the line:\r
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\n" ); document.write( "\n" ); document.write( "------Point-Slope Formula------
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is one of the given points\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-5=%28-6%2F5%29%28x--2%29\" Plug in \"m=-6%2F5\", \"x%5B1%5D=-2\", and \"y%5B1%5D=5\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-5=%28-6%2F5%29%28x%2B2%29\" Rewrite \"x--2\" as \"x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-5=%28-6%2F5%29x%2B%28-6%2F5%29%282%29\" Distribute \"-6%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-5=%28-6%2F5%29x-12%2F5\" Multiply \"-6%2F5\" and \"2\" to get \"-12%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-6%2F5%29x-12%2F5%2B5\" Add \"5\" to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-6%2F5%29x%2B13%2F5\" Combine like terms \"-12%2F5\" and \"5\" to get \"13%2F5\" (note: if you need help with combining fractions, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line which goes through the points (\"-2\",\"5\") and (\"3\",\"-1\") is:\"y=%28-6%2F5%29x%2B13%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "The equation is now in \"y=mx%2Bb\" form (which is slope-intercept form) where the slope is \"m=-6%2F5\" and the y-intercept is \"b=13%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-6%2F5%29x%2B13%2F5\" and plot the points (\"-2\",\"5\") and (\"3\",\"-1\"), we get this: (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-6%2F5%29x%2B13%2F5\" through the points (\"-2\",\"5\") and (\"3\",\"-1\")\r
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