document.write( "Question 1067578: Please help me with this word problem.\r
\n" ); document.write( "\n" ); document.write( "The index of refraction \"+n+\" of a transparent material is the ratio of the speed of light in a vacuum to the speed of light in the material. For the triangular prism in the picture, n = 1.5 and a = 60°. Identify the angle θ for the glass prism if ( see image linked below ) thanks a bunch.\r
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Algebra.Com's Answer #683045 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The picture:
\n" ); document.write( "\"n=sin%28theta%2F2%2Balpha%2F2%29%2Fsin%28theta%2F2%29\"
\n" ); document.write( "\"alpha=60%5Eo\"= prism angle crossed by the light
\n" ); document.write( "\"alpha%2F2=60%5Eo%2F2=30%5Eo\"
\n" ); document.write( "\"theta\"= angle of deviation of the light as it goes through the prism
\n" ); document.write( "\"sin%28alpha%2F2%29=sin%2830%5Eo%29=1%2F2=0.5\"
\n" ); document.write( "\"cos%28alpha%2F2%29=cos%2830%5Eo%29=sqrt%283%29%2F2=0.5sqrt%283%29\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "To calculate \"sin%28theta%2F2%2Balpha%2F2%29\" we need the trigonometric identity formula for a sum of angles:
\n" ); document.write( "\"sin%28A%2BB%29=sin%28A%29%2Acos%28B%29%2Bcos%28A%29%2Asin%28B%29\" .
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\n" ); document.write( "So substituting the expression above,
\n" ); document.write( "and the value \"1.5\" for \"n\"
\n" ); document.write( "in the formula for refractive index, we get
\n" ); document.write( " .
\n" ); document.write( "Multiplying both sides of the equal sign times \"2sin%28theta%2F2%29\",
\n" ); document.write( "we get the equivalent equation
\n" ); document.write( "\"3sin%28theta%2F2%29=sqrt%283%29%2Asin%28theta%2F2%29%2Bcos%28theta%2F2%29\"
\n" ); document.write( "Now, dividing both sides of the equation by \"cos%28theta%2F2%29\" ,
\n" ); document.write( "we get the equivalent equation
\n" ); document.write( " ,
\n" ); document.write( "which simplifies to
\n" ); document.write( "\"3tan%28theta%2F2%29=sqrt%283%29%2Atan%28theta%2F2%29%2B1\" ,
\n" ); document.write( "so
\n" ); document.write( "\"3tan%28theta%2F2%29-sqrt%283%29%2Atan%28theta%2F2%29=1\" --> \"%283-sqrt%283%29%29%2Atan%28theta%2F2%29=1\" --> \"tan%28theta%2F2%29=1%2F%283-sqrt%283%29%29\"
\n" ); document.write( "From
\n" ); document.write( "\"tan%28theta%2F2%29=1%2F%283-sqrt%283%29%29\" , or the more elegantly written equivalent
\n" ); document.write( "\"tan%28theta%2F2%29=%283%2Bsqrt%283%29%29%2F6\" ,
\n" ); document.write( "we can calculate an approximate value for \"tan%28theta%2F2%29\" ,
\n" ); document.write( "for which your calculator would give you an approximate value for \"theta%2F2\" ,
\n" ); document.write( "which can be used to calculate an approximate value for \"theta\" .
\n" ); document.write( "The approximate values would be:
\n" ); document.write( "\"tan%28theta%2F2%29=0.788675\" , \"theta%2F2=38.26%5Eo\" ,
\n" ); document.write( "and \"highlight%28theta=76.52%5Eo%29\" .
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\n" ); document.write( "An exact value would have to be expressed as an inverse tangent function
\n" ); document.write( "\"theta=2%2Atan%5E%28-1%29%28%283%2Bsqrt%283%29%29%2F6%29\" ,
\n" ); document.write( "or if you use the double angle trigonometric identity to calculate that \"tan%28theta%29=%2830%2B14sqrt%283%29%29%2F13\" ,
\n" ); document.write( "\"theta=tan%5E%28-1%29%28%2830%2B14sqrt%283%29%29%2F13%29\" .
\n" ); document.write( "Hopefully no instructor would make you go through all that trouble.
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