document.write( "Question 1067866: Problem Page
\n" ); document.write( "Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
\n" ); document.write( "6
\n" ); document.write( " hours. When Keisha drove home, there was no traffic and the trip only took
\n" ); document.write( "4
\n" ); document.write( " hours. If her average rate was
\n" ); document.write( "22
\n" ); document.write( " miles per hour faster on the trip home, how far away does Keisha live from the mountains?
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Algebra.Com's Answer #683037 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
Constant Travel Rates Rule, RT=D for RATE, TIME, DISTANCE
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document.write( "                    SPEED      TIME      DISTANCE\r\n" );
document.write( "GOING                 r          6          d\r\n" );
document.write( "RETURNING            r+22        4          d\r\n" );
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\r
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\n" ); document.write( "\n" ); document.write( "System of Equations \"system%28%28r%29%286%29=d%2C%28r%2B22%29%284%29=d%29\"\r
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\n" ); document.write( "\n" ); document.write( "Same d both directions;
\n" ); document.write( "\"6r=4%28r%2B22%29\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for r, the speed GOING TO the mountains.
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