document.write( "Question 1067840: A jeweler maker has 20 ounces of a gold alloy worth $160 an ounce and 10 ounce of a silver alloy worth $140 an ounce. How many ounces of another alloy at $124 an ounce must she add to these in order to have a mixture of the three that she can use to make 3-ounce jewelry worth $438 a piece?\r
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document.write( "And I really need to know at $124 an ounce answer. Thank you \n" );
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Algebra.Com's Answer #683025 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A jeweler maker has 20 ounces of a gold alloy worth $160 an ounce and 10 ounce of a silver alloy worth $140 an ounce. \n" ); document.write( " How many ounces of another alloy at $124 an ounce must she add to these in order to have a mixture of the three that she can use to make 3-ounce jewelry worth $438 a piece? \n" ); document.write( ": \n" ); document.write( "The 3 oz item worth $438; 438/3 = $146 an oz is the value of the resulting alloy \n" ); document.write( ": \n" ); document.write( "let x = amt of $124 alloy required \n" ); document.write( "160(20) + 140(10) + 124x = 146(20+10+x) \n" ); document.write( "3200 + 1400 + 124x = 146(x+30) \n" ); document.write( "4600 + 124x = 146x + 4380 \n" ); document.write( "4600 - 4380 = 146x - 124x \n" ); document.write( "220 = 22x \n" ); document.write( "x = 220/22 \n" ); document.write( "x = 10 oz of $124 alloy required\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |