document.write( "Question 1067802: A stone is dropped from a water tower and its velocity increases at a rate of 32 feet per second squared 2. The stone hits the ground with a velocity of 192 feet per second. What is the formula v(t). What is the domain and range? What does the input variable represent? \n" ); document.write( "

Algebra.Com's Answer #683006 by KMST(5328) $\"\"$ $\"About$

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$\"0\"$ feet per second is the initial velocity,
\n" ); document.write( "because the stone was simply let go.
\n" ); document.write( " $\"v%28t%29=0%2B32t\"$ --> $\"highlight%28v%28t%29=32t%29\"$ ,
\n" ); document.write( "where $\"v%28t%29\"$ is the downwards velocity in feet per second,
\n" ); document.write( "and $\"t\"$ is the time in seconds since.
\n" ); document.write( " $\"highlight%28Range=%22%5B+0+%2C+192+%5D%22%29\"$ ,
\n" ); document.write( "because the stone's velocity starts as o feet per second,
\n" ); document.write( "and increases all the way to 192 feet per second.
\n" ); document.write( "The formula for $\"v%28t%29\"$ obviously apply to the time the stone is falling,
\n" ); document.write( "not before it is dropped, and not after it hits the ground.
\n" ); document.write( "so we need to find how long it was falling, by solving
\n" ); document.write( " $\"192=32t\"$ --> $\"t=192%2F32\"$ --> $\"t=6\"$ .
\n" ); document.write( " $\"highlight%28Domain=%22%5B+0+%2C+6+%5D%22%29\"$ ,
\n" ); document.write( "because the formula/function $\"v%28t%29\"$ applies only to
\n" ); document.write( " $\"t=0seconds\"$ (time the stone is dropped),
\n" ); document.write( " $\"t=6seconds\"$ (time the stone hits the ground),
\n" ); document.write( "and all the values of $\"t\"$ in between. \n" ); document.write( "

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