document.write( "Question 1067762: Factor completely and show the check by re-multiplication. If the polynominal is not factorable, write \"prime\".\r
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document.write( "1.) 12x^3-20x^2-8x\r
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document.write( "2.) 42x^2-23x-5\r
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document.write( "Thank you. \n" );
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Algebra.Com's Answer #682892 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 12x^3-20x^2-8x \n" ); document.write( "4x can be divided out \n" ); document.write( "4x(3x^2-5x-2)=4x(3x+1)(x-2) \n" ); document.write( "4x*(3x^2-6x+x-2)=12x^3-24x^2+4x^2-8x \n" ); document.write( "------------------- \n" ); document.write( " 42x^2-23x-5 \n" ); document.write( "divide 42 from first and multiply last term by 42 \n" ); document.write( "x^2-23x-210, which factors into (x+7)(x-30) \n" ); document.write( "divide those by 42 and reduce completely \n" ); document.write( "(x+7/42)(x-30/42)=(x+(1/6))(x-(5/7)) \n" ); document.write( "move the denominator of the fraction in front of the x \n" ); document.write( "(6x+1)(7x-5) \n" ); document.write( "42x^2-30x+7x-5 \n" ); document.write( " |