document.write( "Question 93718: In 3 years, Alex will be 3 times as old as his sister Precy. A year ago, Alex was 7 times as old as Precy.How old are they now? \n" ); document.write( "
Algebra.Com's Answer #68284 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Let A be Alex's present age and P be Precy's present age. \n" ); document.write( ". \n" ); document.write( "If A is Alex's present age, then a year ago he was A-1 years old. And a year ago Precy was \n" ); document.write( "P -1 years old. \n" ); document.write( "At that time Alex's age equaled 7 times Precy's age. So in equation form, a year ago: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We can multiply out the right side to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then add +1 to both sides to get rid of the -1 on the left side and the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Finally, subtract 7P from both sides and we get the standard form: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This is our first equation. Remember it. \n" ); document.write( ". \n" ); document.write( "If A is Alex's current age, then in 3 years his age will be A + 3. And if P is Precy's present \n" ); document.write( "age, then in 3 years she will be P + 3. We are told that at that time Alex's age will be \n" ); document.write( "3 times Precy's age. In equation form this is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Multiply our the right side and you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Get rid of the 3 on the left side by subtracting 3 from both sides to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "And finally, put this equation in standard form by subtracting 3P from both sides to \n" ); document.write( "get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So now we have a set of equations as follows: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We can eliminate A by subtracting the two equations vertically in columns to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This can be solved for P by dividing both sides by -4 to get that P (Precy's present age) \n" ); document.write( "is +3. \n" ); document.write( ". \n" ); document.write( "That means that a year ago Precy was 2 and at that time Alex was 7 times as old as she. Therefore, \n" ); document.write( "a year ago Alex was 7*2 or 14 years old. But that was a year ago. That means that this \n" ); document.write( "year Alex is a year older so he is currently 15. \n" ); document.write( ". \n" ); document.write( "So we have that presently Alex is 15 and Precy is 3. \n" ); document.write( ". \n" ); document.write( "Three years from now Alex will be 18 and Precy will be 6. So at that time Alex will be \n" ); document.write( "3 times as old as Precy. That checks so it appears that our answer is correct. \n" ); document.write( ". \n" ); document.write( "The answer is Alex is now 15 and Precy is now 3. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to see your way through this problem. \n" ); document.write( ". \n" ); document.write( " |