document.write( "Question 93718: In 3 years, Alex will be 3 times as old as his sister Precy. A year ago, Alex was 7 times as old as Precy.How old are they now? \n" ); document.write( "
Algebra.Com's Answer #68284 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Let A be Alex's present age and P be Precy's present age.
\n" ); document.write( ".
\n" ); document.write( "If A is Alex's present age, then a year ago he was A-1 years old. And a year ago Precy was
\n" ); document.write( "P -1 years old.
\n" ); document.write( "At that time Alex's age equaled 7 times Precy's age. So in equation form, a year ago:
\n" ); document.write( ".
\n" ); document.write( "\"A+-+1=7%28P-1%29\"
\n" ); document.write( ".
\n" ); document.write( "We can multiply out the right side to get:
\n" ); document.write( ".
\n" ); document.write( "\"A+-+1+=+7P+-+7\"
\n" ); document.write( ".
\n" ); document.write( "Then add +1 to both sides to get rid of the -1 on the left side and the equation becomes:
\n" ); document.write( ".
\n" ); document.write( "\"A+=+7P+-+6\"
\n" ); document.write( ".
\n" ); document.write( "Finally, subtract 7P from both sides and we get the standard form:
\n" ); document.write( ".
\n" ); document.write( "\"A+-+7P+=+-6\"
\n" ); document.write( ".
\n" ); document.write( "This is our first equation. Remember it.
\n" ); document.write( ".
\n" ); document.write( "If A is Alex's current age, then in 3 years his age will be A + 3. And if P is Precy's present
\n" ); document.write( "age, then in 3 years she will be P + 3. We are told that at that time Alex's age will be
\n" ); document.write( "3 times Precy's age. In equation form this is:
\n" ); document.write( ".
\n" ); document.write( "\"A+%2B+3+=+3%28P%2B3%29\"
\n" ); document.write( ".
\n" ); document.write( "Multiply our the right side and you have:
\n" ); document.write( ".
\n" ); document.write( "\"A+%2B+3+=+3P+%2B+9\"
\n" ); document.write( ".
\n" ); document.write( "Get rid of the 3 on the left side by subtracting 3 from both sides to get:
\n" ); document.write( ".
\n" ); document.write( "\"A+=+3P+%2B+6\"
\n" ); document.write( ".
\n" ); document.write( "And finally, put this equation in standard form by subtracting 3P from both sides to
\n" ); document.write( "get:
\n" ); document.write( ".
\n" ); document.write( "\"A+-+3P+=+6\"
\n" ); document.write( ".
\n" ); document.write( "So now we have a set of equations as follows:
\n" ); document.write( ".
\n" ); document.write( "\"A+-7P+=+-6\"
\n" ); document.write( "\"A+-3P+=+6\"
\n" ); document.write( ".
\n" ); document.write( "We can eliminate A by subtracting the two equations vertically in columns to get:
\n" ); document.write( ".
\n" ); document.write( "\"+-4P+=+-12\"
\n" ); document.write( ".
\n" ); document.write( "This can be solved for P by dividing both sides by -4 to get that P (Precy's present age)
\n" ); document.write( "is +3.
\n" ); document.write( ".
\n" ); document.write( "That means that a year ago Precy was 2 and at that time Alex was 7 times as old as she. Therefore,
\n" ); document.write( "a year ago Alex was 7*2 or 14 years old. But that was a year ago. That means that this
\n" ); document.write( "year Alex is a year older so he is currently 15.
\n" ); document.write( ".
\n" ); document.write( "So we have that presently Alex is 15 and Precy is 3.
\n" ); document.write( ".
\n" ); document.write( "Three years from now Alex will be 18 and Precy will be 6. So at that time Alex will be
\n" ); document.write( "3 times as old as Precy. That checks so it appears that our answer is correct.
\n" ); document.write( ".
\n" ); document.write( "The answer is Alex is now 15 and Precy is now 3.
\n" ); document.write( ".
\n" ); document.write( "Hope this helps you to see your way through this problem.
\n" ); document.write( ".
\n" ); document.write( "
\n" );