document.write( "Question 1067689: In a survey of 504 adults, there is an 89% chance they agreed. 3 adults were surveys, what's the probabality that all 3 agreed? \n" ); document.write( "
| Algebra.Com's Answer #682816 by stanbon(75887)      You can put this solution on YOUR website! In a survey of 504 adults, there is an 89% chance they agreed. 3 adults were surveys, what's the probabality that all 3 agreed? \n" ); document.write( "-------------------------- \n" ); document.write( "Binomial Problem with n = 3 and p = 0.89 \n" ); document.write( "Ans: P(x = 3) = (0.89)^3 = 0.7050 \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |