document.write( "Question 1067689: In a survey of 504 adults, there is an 89% chance they agreed. 3 adults were surveys, what's the probabality that all 3 agreed? \n" ); document.write( "
Algebra.Com's Answer #682816 by stanbon(75887)\"\" \"About 
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In a survey of 504 adults, there is an 89% chance they agreed. 3 adults were surveys, what's the probabality that all 3 agreed?
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\n" ); document.write( "Binomial Problem with n = 3 and p = 0.89
\n" ); document.write( "Ans: P(x = 3) = (0.89)^3 = 0.7050
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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