document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1067633>Question 1067633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please i need help with these questions.<BR>\n" );
document.write( "1. given that(2-3k),(2k+3),(k+7), where k is a constant, are three consecutive terms of linear sequence(A.P),find its common difference.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #682775 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=682775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The nth term of a arithmetic sequence is<BR>\n" );
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document.write( "a(n) = a(1) + d(n-1), where a(1) is the first term and d is the common difference<BR>\n" );
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document.write( "we are given<BR>\n" );
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document.write( "2-3k = a(1) + d(n-1)<BR>\n" );
document.write( "3+2k = a(1) + d(n+1-1) = a(1) + dn<BR>\n" );
document.write( "7+k = a(1) + d(n+2-1) = a(1) + d(n+1)<BR>\n" );
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document.write( "by the definition of an arithmetic sequence, we know that<BR>\n" );
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document.write( "3+2k - (2-3k) = 7+k - (3+2k)<BR>\n" );
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document.write( "5k + 1 = -k + 4<BR>\n" );
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document.write( "6k = 3<BR>\n" );
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document.write( "k = 3/6 = 1/2<BR>\n" );
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document.write( "d = 5(1/2) + 1 = 7/2 = 3.5<BR>\n" );
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