document.write( "Question 93673: 1/3(2x-7)=4 \n" ); document.write( "
Algebra.Com's Answer #68274 by jayanthihemkos@yahoo.com(87)\"\" \"About 
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1/3(2x-7)=4\r
\n" ); document.write( "\n" ); document.write( "==>2x/3 - 7/3 =4\r
\n" ); document.write( "\n" ); document.write( "==> 2x/3 -7/3 +7/3 = 4 +7/3\r
\n" ); document.write( "\n" ); document.write( "==> 2x/3 = (12+7)/3 ( here 3 is the LCD)\r
\n" ); document.write( "\n" ); document.write( "==> 2x/3 = 19/3\r
\n" ); document.write( "\n" ); document.write( "==> 2x /3*3 = 19/3*3\r
\n" ); document.write( "\n" ); document.write( "==> 2x = 19\r
\n" ); document.write( "\n" ); document.write( "==> 2x/2 = 19/ 2\r
\n" ); document.write( "\n" ); document.write( "==> x = 19/2\r
\n" ); document.write( "\n" ); document.write( " ==> x = 9.5\r
\n" ); document.write( "\n" ); document.write( "Hence the solution\r
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