document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93709>Question 93709</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the product of nine and the quanity 5 more than a number tis less than 6<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68263 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The quantity 5 more than t is (5 + t)<BR>\n" );
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document.write( "the product of 9 and that quantity is 9(5+t) which multiplies out to 45 + 9t.<BR>\n" );
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document.write( "Finally, that result is less than 6. So the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=45+%2B+9t+%3C+6 ALIGN=MIDDLE  ALT=\"45+%2B+9t+%3C+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "This inequality is solvable for +t.  Start by getting rid of 45 on the left side by subtracting<BR>\n" );
document.write( "45 from both sides to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+9t+%3C+6+-45 ALIGN=MIDDLE  ALT=\"+9t+%3C+6+-45\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "which simplifies to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9t+%3C+-39 ALIGN=MIDDLE  ALT=\"9t+%3C+-39\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Then you can solve for t by dividing both sides by +9 to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t+%3C+-39%2F9 ALIGN=MIDDLE  ALT=\"t+%3C+-39%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Note that the numerator and denominator of the right side are both divisible by 3. When you divide<BR>\n" );
document.write( "them both by 3 the inequality simplifies to:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t+%3C+-13%2F3 ALIGN=MIDDLE  ALT=\"t+%3C+-13%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "This means that the original inequality will be true whenever t is less than <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-13%2F3 ALIGN=MIDDLE  ALT=\"-13%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "which means whenever t on the number line is to the left of the point <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-13%2F3 ALIGN=MIDDLE  ALT=\"-13%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "That's the answer to the original problem. <BR>\n" );
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document.write( "Hope that this helps you to understand problem wording a little better and shows you the way<BR>\n" );
document.write( "that the problem can be worked all the way to an answer for t.<BR>\n" );
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