document.write( "Question 1067407: The points
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Algebra.Com's Answer #682603 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Whichever placement of the right angle, the hypotenuse will be the segment PQ, and this length is \"sqrt%28%28-3-1%29%5E2%2B%286-4%29%5E2%29=sqrt%2816%2B4%29=sqrt%2820%29=2sqrt%285%29\".\r
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\n" ); document.write( "\n" ); document.write( "Pick the x coordinate 1 and the y coordinate 6 for the right angle point at (1,6) and this should be the point opposite the hypotenuse in quadrant 1.
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