document.write( "Question 1067370: If f(x)=sinx+cos2x,determine which sub-intervals of (0,2pi)
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document.write( "f(x) is increasing on and which intervals f(x) is decreasing. \n" );
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Algebra.Com's Answer #682580 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "If f(x)=sinx+cos2x,determine which sub-intervals of (0,2pi)\r\n" ); document.write( "f(x) is increasing on and which intervals f(x) is decreasing.\r\n" ); document.write( "\r\n" ); document.write( "f(x) = sin(x) + cos(2x)\r\n" ); document.write( "f'(x) = cos(x) - 2sin(2x)\r\n" ); document.write( "\r\n" ); document.write( "We set f'(x)=0 to see if there are any critical\r\n" ); document.write( "values as far as increasing or decreasing:\r\n" ); document.write( "\r\n" ); document.write( "cos(x) - 2sin(2x) = 0\r\n" ); document.write( "\r\n" ); document.write( "cos(x) -2[2sin(x)cos(x)] = 0\r\n" ); document.write( "\r\n" ); document.write( "cos(x) -4sin(x)cos(x) = 0\r\n" ); document.write( "\r\n" ); document.write( "cos(x)[1 - 4sin(x)] = 0\r\n" ); document.write( "\r\n" ); document.write( "cos(x) = 0; 1 - 4sin(x) = 0\r\n" ); document.write( "x =\n" ); document.write( " |