document.write( "Question 93701: solve algebraically\r
\n" ); document.write( "\n" ); document.write( "2x^3-x^2-18x+9=0 \n" ); document.write( "
Algebra.Com's Answer #68250 by stanbon(75887)\"\" \"About 
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solve algebraically\r
\n" ); document.write( "\n" ); document.write( "2x^3-x^2-18x+9=0
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\n" ); document.write( "I graphed it to find a zero at x=-3.
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\n" ); document.write( "Using synthetic division find the other zeroes:
\n" ); document.write( "-3)....2....-1....-18....9
\n" ); document.write( ".........2....-7.....3...|..0\r
\n" ); document.write( "\n" ); document.write( "Remainder = 0 because x=-3 is a zero of the polynomial
\n" ); document.write( "Quotient: 2x^2-7x+3
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\n" ); document.write( "Factor 2x^2-7x+3 using the AC Method:
\n" ); document.write( "2x^2-6x-x+3 =0
\n" ); document.write( "2x(x-3)-(x-3)=0
\n" ); document.write( "(x-3)(2x-1)=0
\n" ); document.write( "x =3 or x=1/2
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\n" ); document.write( "The zeroes of the orignal equation are
\n" ); document.write( "x=-3, x=3, x=1/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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