document.write( "Question 1067263: An actor invested some money at 8% simple interest, and $47,000 more than three times the amount at 11%. The total annual interest earned from the investment was $52,320. How much did he invest at each amount? \n" ); document.write( "
Algebra.Com's Answer #682484 by addingup(3677) You can put this solution on YOUR website! some money: x \n" ); document.write( "three times the amount: 3x. Add 47,000: 3x+47,000 \n" ); document.write( "0.08x+(0.11(3x+47,000) = 52,320 \n" ); document.write( "0.08x+0.33x+5170 = 52.320 \n" ); document.write( "0.41x = 47150 \n" ); document.write( "x = 115,000 is the amount invested at 8% \n" ); document.write( "3(115,000)+47,000 = 392,000 is the amount invested at 11% \n" ); document.write( " |