document.write( "Question 1067185: In triangle ABC,m\n" ); document.write( "m( AC)^2=(mAB)^2+(mBC)^2-(mAB).(mCB)\r
\n" ); document.write( "\n" ); document.write( "ABC is an isosceles triangle in which mAB =mAC.CD is the perpendicular drawn from C to the opposite side .Prove that (mBC)^2=2 (mAB).(mBD).
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Algebra.Com's Answer #682462 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "From the first phrase, cosine of the angle between AB and BC is \"1%2F2\", hence, the angle ABC is 60 degrees.\r
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