document.write( "Question 1067247: the lifetimes of a brand of electric light bulbs are normally distributed with mean 1300hours and standartd deviation 120hours. a light bulb is selected at random and tested by keeping it on continuously \r
\n" ); document.write( "\n" ); document.write( "find the probability that it has a lifetime of over 1540hours?\r
\n" ); document.write( "\n" ); document.write( "its has a lifetime between 1222 and 1540 hours?\r
\n" ); document.write( "\n" ); document.write( "two light bulbs are selected at random.
\n" ); document.write( "find the probability that they both last between 1222 and 1540
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Algebra.Com's Answer #682454 by Boreal(15235)\"\" \"About 
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z=(x-mean)/sd
\n" ); document.write( "=(1540-300/120=2
\n" ); document.write( "probability z>2=0.0228
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\n" ); document.write( "(1222-1300)/120=-78/120=-0.65
\n" ); document.write( "probability -0.65\n" ); document.write( "-----------------
\n" ); document.write( "That would be the probability just obtained squared, since they are independent: 0.5175 if I don't round the last one.
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