document.write( "Question 1067180: Calculate the specific heat of a metal (in calories/gram-degree C) from the following data. A container made of the metal has a mass of 3.80 kg and contains 16.3 kg of water. A 1.40 kg piece of the same metal, initially at a temperature of 150 degrees C, is placed in the water. The container and water initially have a temperature of 15 degrees C, and the final temperature of the entire system is 18 degrees C. \n" ); document.write( "
Algebra.Com's Answer #682376 by ikleyn(52908)\"\" \"About 
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\n" ); document.write( "Calculate the specific heat of a metal (in calories/gram-degree C) from the following data.
\n" ); document.write( "A container made of the metal has a mass of 3.80 kg and contains 16.3 kg of water. A 1.40 kg piece of the same metal,
\n" ); document.write( "initially at a temperature of 150 degrees C, is placed in the water.
\n" ); document.write( "The container and water initially have a temperature of 15 degrees C, and the final temperature of the entire system is 18 degrees C.
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document.write( "A balance equation (the balance of thermal energy) is\r\n" );
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document.write( "\"C%5Bm%5D%2A3.8%2A%2818-15%29+%2B+C%5Bw%5D%2A16.3%2A%2818-15%29\" = \"C%5Bm%5D%2A1.4%2A%28150-18%29\".      (1)\r\n" );
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document.write( "    It says \"amount of heat absorbed by the system to raise its temperature from 15°C to 18°C is the same as the amount of heat \r\n" );
document.write( "    lost by the metal piece when it cooled from 150°C to 15°C).\r\n" );
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document.write( "Here \"C%5Bm%5D\" is the specific heat of the metal  ( in calories/(gram-degree C) ), which is under the question),\r\n" );
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document.write( "     \"C%5Bw%5D\" is the specific heat of water  ( = 1 calorie/(gram-degree C) ).\r\n" );
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document.write( "From (1), express  \"C%5Bm%5D\" = \"%2816.3%2A%2818-15%29%29%2F%281.4%2A%28150-18%29+-+3.8%2A%2818-15%29%29\" = 0.282 calorie/(gram-degree C)\r\n" );
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