document.write( "Question 93475: Using the following form to find the equation of the line with an x-intercept of (-5/6,0) and a y-intercept of (0,-7/3)
\n" ); document.write( "The intercept form of the equation of a line with intercepts at (a,0) and (0,b) is x/a+ y/b=1, a not equal to 0, b not equal to 0.
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Algebra.Com's Answer #68237 by ankor@dixie-net.com(22740)\"\" \"About 
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Using the following form to find the equation of the line with an x-intercept of (-5/6,0) and a y-intercept of (0,-7/3)
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\n" ); document.write( "Using the slope/intercept form: y = mx + b\r
\n" ); document.write( "\n" ); document.write( "Using the y intercept 0,-7/3: then y = mx - (7/3)
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\n" ); document.write( "Using the x intercept -5/6, 0; find m:
\n" ); document.write( "(-5/6)m - (7/3) = 0
\n" ); document.write( "(-5/6m) = +(7/3)
\n" ); document.write( "m = (7/3)/(-5/6)
\n" ); document.write( "Which is:
\n" ); document.write( "m = (7/3)*(-6/5)
\n" ); document.write( "m = -42/15 = -14/5
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\n" ); document.write( "The equation: y = \"-14%2F5\"x - \"7%2F3\"
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\n" ); document.write( "The intercept form of the equation of a line with intercepts at (a,0) and (0,b) is x/a+ y/b=1, a not equal to 0, b not equal to 0.
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\n" ); document.write( "Put in the y = mx + b form
\n" ); document.write( "x/a + y/b = 1
\n" ); document.write( "y/b = -x/a + 1; subtracted x/a from both sides
\n" ); document.write( "y = -bx/a + b; multiply both sides by b
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\n" ); document.write( "Hope this is what you mean here\r
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